A body of mass m is moving with uniform accel | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given that the body starts from rest (implied by uniform acceleration starting from $t=0$),the acceleration $a$ is given by $a = \frac{v - 0}{t_1}

Vedclass · Accepted Answer

$\frac{1}{2} m \frac{v^2}{t_1^2} t^2$

Vedclass · Answer

(D) Given that the body starts from rest (implied by uniform acceleration starting from $t=0$),the acceleration $a$ is given by $a = \frac{v - 0}{t_1} = \frac{v}{t_1}$.At any time $t$,the velocity $v_t$ of the body is $v_t = u + at = 0 + \left( \frac{v}{t_1} \right) t = \frac{v}{t_1} t$.According to the Work-Energy Theorem,the work done $W$ is equal to the change in kinetic energy:$W = \Delta K = \frac{1}{2} m v_t^2 - 0$.Substituting the value of $v_t$:$W = \frac{1}{2} m \left( \frac{v}{t_1} t \right)^2 = \frac{1}{2} m \frac{v^2}{t_1^2} t^2$.

$A$ body of mass $m$ is moving with uniform acceleration such that at time $t_1$ its velocity is $v$. What is the work done on the body at any time $t$?

Similar Questions

$A$ lorry and a car moving with the same kinetic energy $(K.E.)$ are brought to rest by applying the same retarding force. Then:

$A$ stone with weight $w$ is thrown vertically upward into the air from ground level with initial speed $v_0$. If a constant force $f$ due to air drag acts on the stone throughout its flight,the maximum height attained by the stone is

$A$ light rod of length $L$ is pivoted at its upper end. Two masses (each of mass $m$) are attached to the rod,one at its midpoint and the other at its free end. What horizontal velocity must be imparted to the lower end so that the rod reaches the horizontal position?

$A$ pendulum bob on a $2\, m$ string is displaced $60^\circ$ from the vertical and then released. What is the speed of the bob as it passes through the lowest point in its path? (Take $g = 9.8\, m/s^2$)

$A$ body is projected vertically upwards with an initial velocity of $7 \, m/s$. At what height will its kinetic energy become half of its initial value (in $, m$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module