(A) The potential energy of the ice block at height $h$ is converted into kinetic energy,which is then converted into heat upon impact.Let $m$ be the

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(A) The potential energy of the ice block at height $h$ is converted into kinetic energy,which is then converted into heat upon impact.Let $m$ be the mass of the ice block and $k$ be the fraction of ice that melts.The potential energy $PE = mgh$.The heat required to melt a fraction $k$ of the ice is $Q = k \cdot m \cdot L$.Equating the energy: $mgh = kmL$.Therefore,$k = \frac{gh}{L}$.Given $g = 10 \ m/s^{2}$,$h = 1000 \ m$,and $L = 3.36 \times 10^{5} \ J/kg$.$k = \frac{10 \times 1000}{3.36 \times 10^{5}} = \frac{10000}{336000} = \frac{1}{33.6} \approx \frac{1}{33}$.

Class 11 Physics 10-1.Thermometry, Thermal Expansion and Calorimetry Mix Examples-Thermometry, Thermal Expansion and Calorimetry

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$A$ block of ice at $0^{\circ}C$ falls from a height of $1 \ km$ onto an insulating surface. If all its kinetic energy is converted into heat,what fraction of the ice will melt? (Take $g = 10 \ m/s^{2}$ and latent heat of fusion of ice $L = 3.36 \times 10^{5} \ J/kg$)

A
$\frac{1}{33}$
B
$\frac{1}{8}$
C
$\frac{1}{33} \times 10^{-4}$
D
All of it will melt

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10-1.Thermometry, Thermal Expansion and Calorimetry

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Mix Examples-Thermometry, Thermal Expansion and Calorimetry

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$A$ lead bullet moving with velocity '$v$' strikes a wall and stops. If $50\%$ of its energy is converted into heat,then the increase in temperature is ($s =$ specific heat of lead,$J =$ mechanical equivalent of heat).

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$A$ block of ice at $0^{\circ}C$ falls from a height of $1 \ km$ onto an insulating surface. If all its kinetic energy is converted into heat,what fraction of the ice will melt? (Take $g = 10 \ m/s^{2}$ and latent heat of fusion of ice $L = 3.36 \times 10^{5} \ J/kg$)

Similar Questions

Heat needed to convert $1 \ kg$ of ice at $0^{\circ} C$ to steam at $100^{\circ} C$ is

If two balls of the same metal weighing $5\, g$ and $10\, g$ strike a target with the same velocity,and the heat energy developed is used solely for raising their temperature,then the temperature rise will be higher:

Find the quantity of heat required to convert $40 \; g$ of ice at $-20^{\circ} C$ into water at $20^{\circ} C$. Given $L_{\text{ice}} = 0.336 \times 10^6 \; J/kg$,specific heat of ice $= 2100 \; J/kg \cdot K$,and specific heat of water $= 4200 \; J/kg \cdot K$. (in $; J$)

$A$ thermocouple produces $40 \, \mu V/K$. The temperatures of the cold and hot junctions are $40 \, ^\circ C$ and $20 \, ^\circ C$ respectively. If $150$ such thermocouples are connected in series,what is the total thermo-emf produced in $mV$?

$A$ lead bullet moving with velocity '$v$' strikes a wall and stops. If $50\%$ of its energy is converted into heat,then the increase in temperature is ($s =$ specific heat of lead,$J =$ mechanical equivalent of heat).

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