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(D) The rate of heat flow $H$ through a cylindrical rod is given by the formula: $H = \frac{dQ}{dt} = \frac{KA(T_1 - T_2)}{L}$.Here,$K$ is the thermal

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Length $1 \ m$; Radius $2 \ cm$

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(D) The rate of heat flow $H$ through a cylindrical rod is given by the formula: $H = \frac{dQ}{dt} = \frac{KA(T_1 - T_2)}{L}$.Here,$K$ is the thermal conductivity,$A$ is the cross-sectional area,$T_1 - T_2$ is the temperature difference,and $L$ is the length of the rod.Since $A = \pi r^2$,the rate of heat flow is proportional to $\frac{r^2}{L}$.Let's calculate the ratio $\frac{r^2}{L}$ for each option:$A: \frac{1^2}{1} = 1$$B: \frac{1^2}{2} = 0.5$$C: \frac{2^2}{2} = 2$$D: \frac{2^2}{1} = 4$Comparing the values,option $D$ has the highest ratio,meaning it will conduct the most heat.

Which of the following cylindrical rods will conduct the most heat when their ends are maintained at the same steady temperatures?

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