A photodetector is fabricated from a semicond | vedclass

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(B) The energy of the incident photon must be at least equal to the band gap energy $E_g$ to excite an electron from the valence band to the conductio

Vedclass · Accepted Answer

$1703$

Vedclass · Answer

(B) The energy of the incident photon must be at least equal to the band gap energy $E_g$ to excite an electron from the valence band to the conduction band.Thus,$E = \frac{hc}{\lambda} = E_g$.Rearranging for wavelength: $\lambda = \frac{hc}{E_g}$.Given $h = 6.63 	imes 10^{-34} \, J \cdot s$,$c = 3 	imes 10^8 \, m/s$,and $E_g = 0.73 \, eV = 0.73 	imes 1.6 	imes 10^{-19} \, J$.Substituting the values:$\lambda = \frac{6.63 	imes 10^{-34} 	imes 3 	imes 10^8}{0.73 	imes 1.6 	imes 10^{-19}} \, m$.$\lambda \approx 1.703 	imes 10^{-6} \, m = 1703 \, nm$.

$A$ photodetector is fabricated from a semiconductor with a band gap $E_g = 0.73 \, eV$. What is the maximum wavelength (in $nm$) it can detect?

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