A particle moves on a circular path with decr | vedclass

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(D) When a particle moves in a circular path,its position vector $\vec{r}$ and velocity vector $\vec{v}$ lie in the plane of the circle.The angular mo

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The direction of angular momentum remains constant.

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(D) When a particle moves in a circular path,its position vector $\vec{r}$ and velocity vector $\vec{v}$ lie in the plane of the circle.The angular momentum is given by $\vec{L} = \vec{r} 	imes \vec{p} = m(\vec{r} 	imes \vec{v})$.Since the motion is confined to a fixed plane (the plane of the circle),the cross product $\vec{r} 	imes \vec{v}$ always points in a direction perpendicular to the plane of the circle according to the right-hand rule.Even if the speed of the particle changes,the direction of the angular momentum vector remains constant (perpendicular to the plane of motion).Therefore,the correct statement is that the direction of angular momentum remains constant.

$A$ particle moves on a circular path with decreasing speed. Identify the correct statement.

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