An artificial satellite of mass 500 kg is or | vedclass

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Question

(A) The relationship between areal velocity $(\frac{dA}{dt})$ and angular momentum $(L)$ for a satellite of mass $(m)$ is given by the formula: $\frac

Vedclass · Accepted Answer

$4 	imes 10^7 \ kg \ m^2s^{-1}$

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(A) The relationship between areal velocity $(\frac{dA}{dt})$ and angular momentum $(L)$ for a satellite of mass $(m)$ is given by the formula: $\frac{dA}{dt} = \frac{L}{2m}$.Given:Mass $(m) = 500 \ kg$Areal velocity $(\frac{dA}{dt}) = 4 	imes 10^4 \ m^2s^{-1}$.Rearranging the formula to solve for angular momentum $(L)$:$L = 2m 	imes \frac{dA}{dt}$.Substituting the given values:$L = 2 	imes 500 	imes (4 	imes 10^4)$.$L = 1000 	imes 4 	imes 10^4$.$L = 4 	imes 10^7 \ kg \ m^2s^{-1}$.Therefore,the angular momentum is $4 	imes 10^7 \ kg \ m^2s^{-1}$.

An artificial satellite of mass $500 \ kg$ is orbiting the Earth. If its areal velocity is $4 \times 10^4 \ m^2s^{-1}$,find its angular momentum.

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