The linear mass density of a rod of length $L$ varies as $\lambda = A + Bx$. Find the center of mass.

  • A
    $\frac{L(3A + 3BL)}{2(2A + BL)}$
  • B
    $\frac{L(3A + 2BL)}{3(2A + 3BL)}$
  • C
    $\frac{L(3A + 2BL)}{3(2A + BL)}$
  • D
    $\frac{L(A + BL)}{3(A + BL)}$

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