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(D) The initial temperature $T_1 = -73 + 273 = 200 \ K$.The final temperature $T_2 = 327 + 273 = 600 \ K$.According to the Stefan-Boltzmann law,the em

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$1/81$

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(D) The initial temperature $T_1 = -73 + 273 = 200 \ K$.The final temperature $T_2 = 327 + 273 = 600 \ K$.According to the Stefan-Boltzmann law,the emissive power $W$ is proportional to the fourth power of the absolute temperature: $W \propto T^4$.Therefore,the ratio of the emissive powers is $\frac{W_1}{W_2} = \left( \frac{T_1}{T_2} \right)^4$.Substituting the values: $\frac{W_1}{W_2} = \left( \frac{200}{600} \right)^4 = \left( \frac{1}{3} \right)^4 = \frac{1}{81}$.Thus,the ratio of the emissive power is $1:81$.

If the temperature of a body is increased from $-73^{\circ}C$ to $327^{\circ}C$,the ratio of its emissive power will be ...

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