The value of $1 \, \text{a.m.u.}$ is equivalent to how many $MeV/c^2$?

$A$ nucleus $^{A}_{Z} X$ has mass represented by $M(A, Z)$. If $M_p$ and $M_n$ denote the mass of a proton and a neutron respectively, and $B.E.$ is the binding energy in $MeV$, then:

The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energies of the nuclei $_{20}^{41} Ca$ and $_{13}^{27} Al$ from the following data:
$m(_{20}^{40} Ca) = 39.962591 \; u$
$m(_{20}^{41} Ca) = 40.962278 \; u$
$m(_{13}^{26} Al) = 25.986895 \; u$
$m(_{13}^{27} Al) = 26.981541 \; u$
(Given mass of neutron $m_n = 1.008665 \; u$)

What is the energy equivalent to one kilogram of mass?

Assume the graph of specific binding energy versus mass number is as shown in the figure. Using this graph,select the correct choice from the following.

Calculate the binding energy of a nitrogen nucleus $\left[{ }_7^{14} N\right]$,given that the mass of the nucleus $m\left[{ }_7^{14} N\right] = 14.00307 \ u$. (Take mass of proton $m_p = 1.00783 \ u$ and mass of neutron $m_n = 1.00867 \ u$) (in $MeV$)