The emission of continuous $X$-rays is due to:
- ATransition of electrons from higher energy level to lower energy level in the target atom.
- BDeceleration of incident electrons as they enter the target atom.
- CTransition of electrons from lower energy level to higher energy level in the target atom.
- DNeutralization of incident electrons.
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Similar Questions
In tungsten,the energy of a $K$-shell electron is $20 \, keV$ and that of an $L$-shell electron is $2 \, keV$. When an electron jumps from the $L$ shell to the $K$ shell,the wavelength of the emitted $X$-ray photon will be:
Medium
View SolutionThe binding energy of the innermost electron in tungsten is $40 \text{ keV}$. To produce characteristic $X$-rays using a tungsten target in an $X$-ray tube,the potential difference $V$ between the cathode and the anti-cathode should be:
When the potential difference applied to an $X$-ray tube is increased, the resulting emitted radiation shows:
Medium
View SolutionThe shortest wavelength of $X-$rays emitted from an $X-$ray tube depends upon
The $K_\alpha$ $X$-ray emission line for tungsten occurs at $\lambda = 0.021 \ nm$. What is the energy difference between the $K$ and $L$ levels in this atom in $keV$?
Medium
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