The mass number of He is 4 and the mass numbe | vedclass

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(B) The mass number of $He$ is $A_{He} = 4$ and the mass number of $S$ is $A_S = 32$.The radius of a nucleus is given by the formula $R = R_0 A^{1/3}$

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$2$

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(B) The mass number of $He$ is $A_{He} = 4$ and the mass number of $S$ is $A_S = 32$.The radius of a nucleus is given by the formula $R = R_0 A^{1/3}$,which implies $R \propto A^{1/3}$.Therefore,the ratio of the radii is given by:$\frac{R_S}{R_{He}} = \left( \frac{A_S}{A_{He}} \right)^{1/3}$Substituting the values:$\frac{R_S}{R_{He}} = \left( \frac{32}{4} \right)^{1/3} = (8)^{1/3} = 2$.Thus,the radius of the $S$ nucleus is $2$ times the radius of the $He$ nucleus.

The mass number of $He$ is $4$ and the mass number of $S$ is $32$. How many times is the radius of the $S$ nucleus compared to the radius of the $He$ nucleus?

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