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Question

(A) The energy released per fission is $E = 250 	ext{ MeV} = 250 	imes 10^6 	ext{ eV}$.Converting this to Joules: $E = 250 	imes 10^6 	imes 1.6 \

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$1600$

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(A) The energy released per fission is $E = 250 	ext{ MeV} = 250 	imes 10^6 	ext{ eV}$.Converting this to Joules: $E = 250 	imes 10^6 	imes 1.6 	imes 10^{-19} 	ext{ J} = 4 	imes 10^{-11} 	ext{ J}$.The total energy produced per second (input power) is $P_{	ext{in}} = 	ext{Number of fissions per second} 	imes E$.$P_{	ext{in}} = 10^{14} 	imes 4 	imes 10^{-11} 	ext{ J/s} = 4000 	ext{ W}$.The efficiency of the reactor is $\eta = 40\% = 0.4$.The power output is $P_{	ext{out}} = \eta 	imes P_{	ext{in}}$.$P_{	ext{out}} = 0.4 	imes 4000 	ext{ W} = 1600 	ext{ W}$.

$A$ nuclear reactor with $40\%$ efficiency produces $10^{14}$ fissions per second. Each fission releases $250 \text{ MeV}$ of energy. The power output of the reactor is ......... $W$.

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