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(A) The total charge enclosed by the cube is $Q_{enclosed} = -q + 3q - q = q$.According to Gauss's Law,the total flux through the cube is $\Phi_{total

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The net electric flux crossing the plane $x = +a/2$ is equal to the net flux crossing the plane $x = -a/2$.

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(A) The total charge enclosed by the cube is $Q_{enclosed} = -q + 3q - q = q$.According to Gauss's Law,the total flux through the cube is $\Phi_{total} = \frac{q}{\epsilon_0}$.Since the charges are placed on the $y$-axis,the configuration is symmetric with respect to the $x$ and $z$ coordinates.The planes $x = +a/2$ and $x = -a/2$ are equidistant from the $y$-axis,and the charge distribution is symmetric relative to these planes,so the flux through them is equal.Similarly,the planes $z = +a/2$ and $z = -a/2$ are symmetric,and the flux through them is equal.Thus,the flux through $x = +a/2$ is equal to the flux through $x = -a/2$.

Consider a cube of side length '$a$' centered at the origin. It is enclosed by three fixed point charges: $(-q)$ at $(0, -a/4, 0)$,$(+3q)$ at $(0, 0, 0)$,and $(-q)$ at $(0, a/4, 0)$. Choose the correct option.

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