(A) The potential energy $U$ of an electric dipole in a uniform electric field $\vec E$ is given by the formula: $U = -\vec p \cdot \vec E = -pE \cos

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$[\vec p]$ and $[\vec E]$ are in the same direction.

(A) The potential energy $U$ of an electric dipole in a uniform electric field $\vec E$ is given by the formula: $U = -\vec p \cdot \vec E = -pE \cos \theta$,where $\theta$ is the angle between the dipole moment $\vec p$ and the electric field $\vec E$.For the potential energy to be minimum,the value of $\cos \theta$ must be maximum.The maximum value of $\cos \theta$ is $1$,which occurs when $\theta = 0^\circ$.This means the dipole moment $\vec p$ and the electric field $\vec E$ must be in the same direction.

Class 12 Physics Electric Potential and Capacitance Electric potential and Potential Energy of dipole

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The condition for minimum potential energy of an electric dipole in a uniform electric field is ......

A
$[\vec p]$ and $[\vec E]$ are in the same direction.
B
$[\vec p]$ and $[\vec E]$ are in opposite directions.
C
$[\vec p]$ and $[\vec E]$ are perpendicular to each other.
D
The potential energy of an electric dipole is always constant under all conditions.

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Electric Potential and Capacitance

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Electric potential and Potential Energy of dipole

When a dipole placed parallel to electric field is rotated through $\pi^c$, the work done is $W$. The work done in rotating the dipole through $(\frac{\pi}{3})^c$ is $(\cos 0^\circ = 1, \cos 60^\circ = \frac{1}{2}, \cos 180^\circ = -1)$

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Two equal charges $q$ are placed at a distance of $2a$ and a third charge $-2q$ is placed at the midpoint. The potential energy of the system is:

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Three charges $-q, Q$ and $-q$ are placed respectively at equal distances on a straight line. If the potential energy of the system of three charges is zero,then what is the ratio of $Q: q$ ?

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Two charges ${q_1}$ and ${q_2}$ are placed $30\,cm$ apart,as shown in the figure. $A$ third charge ${q_3}$ is moved along the arc of a circle of radius $40\,cm$ from $C$ to $D$. The change in the potential energy of the system is $\frac{{{q_3}}}{{4\pi {\varepsilon _0}}}k$,where $k$ is:

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$A$ short electric dipole has a dipole moment of $16 \times 10^{-9} \, Cm$. The electric potential due to the dipole at a point at a distance of $0.6 \, m$ from the centre of the dipole,situated on a line making an angle of $60^{\circ}$ with the dipole axis is $.........V$. (Given: $\frac{1}{4 \pi \epsilon_{0}} = 9 \times 10^{9} \, Nm^{2}/C^{2}$)

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The condition for minimum potential energy of an electric dipole in a uniform electric field is ......

Similar Questions

When a dipole placed parallel to electric field is rotated through $\pi^c$, the work done is $W$. The work done in rotating the dipole through $(\frac{\pi}{3})^c$ is $(\cos 0^\circ = 1, \cos 60^\circ = \frac{1}{2}, \cos 180^\circ = -1)$

Two equal charges $q$ are placed at a distance of $2a$ and a third charge $-2q$ is placed at the midpoint. The potential energy of the system is:

Three charges $-q, Q$ and $-q$ are placed respectively at equal distances on a straight line. If the potential energy of the system of three charges is zero,then what is the ratio of $Q: q$ ?

Two charges ${q_1}$ and ${q_2}$ are placed $30\,cm$ apart,as shown in the figure. $A$ third charge ${q_3}$ is moved along the arc of a circle of radius $40\,cm$ from $C$ to $D$. The change in the potential energy of the system is $\frac{{{q_3}}}{{4\pi {\varepsilon _0}}}k$,where $k$ is:

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