(C) The potential gradient is defined as the rate of change of potential with respect to distance,given by the formula: $E = \frac{V}{d}$.Given:Potent

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(C) The potential gradient is defined as the rate of change of potential with respect to distance,given by the formula: $E = \frac{V}{d}$.Given:Potential $V = 20 \ kV = 20,000 \ V = 2 \times 10^4 \ V$.Distance $d = 2 \ mm = 2 \times 10^{-3} \ m$.Substituting the values into the formula:$E = \frac{2 \times 10^4 \ V}{2 \times 10^{-3} \ m} = 1 \times 10^{4 - (-3)} \ V/m = 10^7 \ V/m$.Thus,the potential gradient is $10^7 \ V/m$.

Class 12 Physics Electric Potential and Capacitance Relation between Electric Field and Potential and Potential Gradient

Easy

$A$ parallel plate capacitor has a potential of $20 \ kV$ and a capacitance of $2 \times 10^{-4} \ \mu F$. If the area of the plate is $0.01 \ m^2$ and the distance between the plates is $2 \ mm$,find the potential gradient.

A
$10^{-7} \ V/m$
B
$10^{-5} \ V/m$
C
$10^7 \ V/m$
D
$10^3 \ V/m$

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Electric Potential and Capacitance

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Relation between Electric Field and Potential and Potential Gradient

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EasyGUJCET 2013

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Two metal plates are separated by $2 \,cm$. The potentials of the plates are $-10 \,V$ and $+30 \,V$. The electric field between the two plates is: (in $\,V/m$)

MediumKCET 2019

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$A$ parallel plate capacitor has a potential of $20 \ kV$ and a capacitance of $2 \times 10^{-4} \ \mu F$. If the area of the plate is $0.01 \ m^2$ and the distance between the plates is $2 \ mm$,find the potential gradient.

Similar Questions

The electrostatic potential inside a charged spherical ball is given by $V = b - ar^2$,where $r$ is the distance from the centre; $a$ and $b$ are constants. Then,the charge density inside the ball is:

In a certain region,the electric potential is given by $V = 6x - 8xy^2 - 8y + 6yz - 4z^2 \, V$. The magnitude of the force on a charge of $2 \, C$ at the origin is ........ $N$.

Variation in electric potential is maximum if one goes

The electric potential at any point $(x, y, z)$ (all in meters) in space is given by $V = 5x^2$ volt. The electric field at the point $(1, 2, 3) \text{ m}$ is $\overrightarrow{E} = $ . . . . . . $\text{N/C}$.

Two metal plates are separated by $2 \,cm$. The potentials of the plates are $-10 \,V$ and $+30 \,V$. The electric field between the two plates is: (in $\,V/m$)

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