Two capacitors of capacitance 2 mu F and 4 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) When capacitors are connected in series,the charge $Q$ stored on each capacitor is the same.The energy stored in a capacitor is given by the formu

Vedclass · Accepted Answer

$2 : 1$

Vedclass · Answer

(A) When capacitors are connected in series,the charge $Q$ stored on each capacitor is the same.The energy stored in a capacitor is given by the formula $U = \frac{Q^2}{2C}$.Since $Q$ is constant for both capacitors in a series connection,the energy $U$ is inversely proportional to the capacitance $C$ $(U \propto \frac{1}{C})$.Therefore,the ratio of the energy stored in the two capacitors is:$\frac{U_1}{U_2} = \frac{C_2}{C_1}$Given $C_1 = 2 \ \mu F$ and $C_2 = 4 \ \mu F$:$\frac{U_1}{U_2} = \frac{4 \ \mu F}{2 \ \mu F} = \frac{2}{1}$Thus,the ratio of the energy stored is $2 : 1$.

Two capacitors of capacitance $2 \ \mu F$ and $4 \ \mu F$ are connected in series. If a potential difference of $10 \ V$ is applied across this combination,what will be the ratio of the energy stored in these capacitors?

Similar Questions

$A$ cylindrical capacitor has charge $Q$ and length $L$. If both the length and the charge are doubled (keeping other parameters constant),the energy stored in the capacitor will:

$A$ battery does $200 \, J$ of work in charging a capacitor. The energy stored in the capacitor is ......... $J$.

The work done in placing a charge of $8 \times 10^{-18} \ C$ on a capacitor of $800 \ \mu F$ is:

Two capacitors,each of value $10 \ \mu F$,are connected in parallel and charged to $200 \ V \ DC$. What is the energy stored in the combination in Joules?

The energy stored in the electric field produced by a metal sphere is $4.5\, J$. If the sphere contains $4\,\mu C$ charge,its radius will be.......$mm$. [Take: $\frac{1}{4\pi\varepsilon_0} = 9 \times 10^9\, N\cdot m^2/C^2$]

Vedclass Test Series

Exam Paper Generator

Online Exam Module