(B) The electric field component $E_y$ along the $Y$-axis is given by the negative potential gradient: $E_y = -\frac{\Delta V}{\Delta y}$.Given: $q =

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(B) The electric field component $E_y$ along the $Y$-axis is given by the negative potential gradient: $E_y = -\frac{\Delta V}{\Delta y}$.Given: $q = 4 \ \mu C = 4 \times 10^{-6} \ C$,$\Delta V = V_B - V_A = 54.8 \ V - 56 \ V = -1.2 \ V$,and $\Delta y = y_B - y_A = 12.5 \ cm - 12.3 \ cm = 0.2 \ cm = 0.2 \times 10^{-2} \ m$.The electric field is $E_y = -\frac{-1.2}{0.2 \times 10^{-2}} = \frac{1.2}{0.002} = 600 \ V/m$.The force component $F_y$ on the charge $q$ is $F_y = q E_y = (4 \times 10^{-6} \ C) \times (600 \ V/m) = 2400 \times 10^{-6} \ N = 24 \times 10^{-4} \ N$.

Class 12 Physics Electric Potential and Capacitance Relation between Electric Field and Potential and Potential Gradient

Medium

Two points $A$ and $B$ on the $Y$-axis are at distances of $12.3 \ cm$ and $12.5 \ cm$ from the origin,respectively. The potentials at these points are $56 \ V$ and $54.8 \ V$,respectively. What is the component of the force on a charge of $4 \ \mu C$ placed at point $A$ on the $Y$-axis?

A
$2.4 \times 10^{-4} \ N$
B
$24 \times 10^{-4} \ N$
C
$2 \times 10^{-4} \ N$
D
$24 \times 10^{-8} \ N$

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Electric Potential and Capacitance

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Relation between Electric Field and Potential and Potential Gradient

As shown in the figure, if the values of the electric potential at three points $A, B$ and $C$ in a uniform electric field $(\vec{E})$ are $V_A, V_B$, and $V_C$ respectively, then

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The electric potential $V$ is given as a function of distance $x$ (metre) by $V = (4x^2 + 8x - 3) \ V$. The value of the electric field at $x = 0.5 \ m$,in $V/m$,is:

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$A$ charge of $5\,C$ experiences a force of $5000\,N$ when it is kept in a uniform electric field. What is the potential difference $V$ (in volts) between two points separated by a distance of $1\,cm$?

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The electrostatic potential in a charged spherical region of radius $r$ varies as $V = ar^3 + b$, where $a$ and $b$ are constants. The total charge in the sphere of unit radius is $\alpha \times \pi a \epsilon_0$. The value of $\alpha$ is . . . . . . .

MediumJEE MAIN 2026

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Electric field in a region is given by $\vec{E} = Ax\hat{i} + By\hat{j}$, where $A = 10 \ V/m^2$ and $B = 5 \ V/m^2$. If the electric potential at a point $(10, 20)$ is $500 \ V$, then the electric potential at the origin is . . . . . . $V$.

DifficultJEE MAIN 2026

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Two points $A$ and $B$ on the $Y$-axis are at distances of $12.3 \ cm$ and $12.5 \ cm$ from the origin,respectively. The potentials at these points are $56 \ V$ and $54.8 \ V$,respectively. What is the component of the force on a charge of $4 \ \mu C$ placed at point $A$ on the $Y$-axis?

Similar Questions

As shown in the figure, if the values of the electric potential at three points $A, B$ and $C$ in a uniform electric field $(\vec{E})$ are $V_A, V_B$, and $V_C$ respectively, then

The electric potential $V$ is given as a function of distance $x$ (metre) by $V = (4x^2 + 8x - 3) \ V$. The value of the electric field at $x = 0.5 \ m$,in $V/m$,is:

$A$ charge of $5\,C$ experiences a force of $5000\,N$ when it is kept in a uniform electric field. What is the potential difference $V$ (in volts) between two points separated by a distance of $1\,cm$?

The electrostatic potential in a charged spherical region of radius $r$ varies as $V = ar^3 + b$, where $a$ and $b$ are constants. The total charge in the sphere of unit radius is $\alpha \times \pi a \epsilon_0$. The value of $\alpha$ is . . . . . . .

Electric field in a region is given by $\vec{E} = Ax\hat{i} + By\hat{j}$, where $A = 10 \ V/m^2$ and $B = 5 \ V/m^2$. If the electric potential at a point $(10, 20)$ is $500 \ V$, then the electric potential at the origin is . . . . . . $V$.

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