The equivalent capacitance between points $a$ and $b$ in the given circuit is ........ $\mu F$.

Five capacitors are connected to a $DC$ potential of $100\,V$ as shown in the figure. Find the charge in the $10\,\mu F$ capacitor (in $\mu C$).

The difference between the equivalent capacitances of two identical capacitors connected in parallel and in series is $6 \mu F$. The value of the capacitance of each capacitor is (in $\mu F$)

Find the net capacitance between $A$ and $B$.

When three capacitors of equal capacities are connected in parallel and one of the same capacity is connected in series with the combination,the resultant capacity is $4.5 \mu F$. The capacity of each capacitor is: (in $\mu F$)

Three capacitors,each of value $1 \ \mu\text{F}$,are connected in such a way that the resultant capacitance is $1.5 \ \mu\text{F}$. Then: