Find the potential difference between points $x$ and $y$.

  • A
    $\frac{({C_4}{C_1} + {C_2}{C_3})}{({C_3} + {C_4})({C_1} + {C_2})}E$
  • B
    $\frac{({C_4}{C_1} - {C_2}{C_3})}{({C_3} - {C_4})({C_1} - {C_2})}E$
  • C
    $\frac{({C_4}{C_1} - {C_2}{C_3})}{({C_3} + {C_4})({C_1} + {C_2})}E$
  • D
    $\frac{({C_4}{C_1} + {C_2}{C_3})}{({C_3} + {C_4})({C_1} - {C_2})}E$

Explore More

Similar Questions

In the circuit shown in the figure,$C_1 = C_2 = 2 \mu F$. Find the charge stored in the capacitors.

Difficult
View Solution

Consider an infinite matrix of capacitors as shown in the figure. The effective capacitance between point $A$ and $B$ will be

Difficult
View Solution

In the given figure,the charge stored in $6 \ \mu F$ capacitor,when points $A$ and $B$ are joined by a connecting wire is . . . . . . $\mu C$.

Find the potential difference $V_a - V_b$ between the points $a$ and $b$ shown in the figure.

Difficult
View Solution

$A$ composite parallel plate capacitor is made up of two different dielectric materials with different thicknesses ($t_{1} = 0.5 \text{ mm}$ and $t_{2} = 1 \text{ mm}$) and dielectric constants ($\epsilon_{r1} = 3$ and $\epsilon_{r2} = 4$) as shown in the figure. The two dielectric materials are separated by a conducting foil $F$. The voltage of the conducting foil is $.....V$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo