Two capacitors of $1 \ \mu F$ and $2 \ \mu F$ are connected in series. This combination is charged to a potential difference of $120 \ V$. What is the potential difference across the $1 \ \mu F$ capacitor in volts?

Two capacitors of capacitance $4\,\mu F$ and $6\,\mu F$ are connected in series. $A$ potential difference of $500\;V$ is applied to the outer plates of the two-capacitor system. The charge on each capacitor is numerically:

Three parallel plate capacitors of capacitances $4 \mu F$,$6 \mu F$ and $12 \mu F$ are first connected in series and then in parallel. The ratio of the effective capacitances in the two cases is

Figure $(a)$ shows two capacitors connected in series and joined to a battery. The graph in figure $(b)$ shows the variation in potential as one moves from left to right on the branch containing the capacitors. If the graph represents the potential across the capacitors,then:

The minimum number of capacitors each of $2 \ \mu F$ required to make a circuit with an equivalent capacitance of $5 \ \mu F$ is

An infinite number of capacitors with capacitances $C, 4C, 16C, ... \infty$ are connected in series. What is the equivalent capacitance of the combination in terms of $C$?