In a P-type semiconductor, the acceptor level | vedclass

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(B) The energy required to create a hole is given by the acceptor level energy $E = 57 	ext{ meV} = 57 	imes 10^{-3} 	ext{ eV}$.Using the relation

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$217100$

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(B) The energy required to create a hole is given by the acceptor level energy $E = 57 	ext{ meV} = 57 	imes 10^{-3} 	ext{ eV}$.Using the relation $E = \frac{hc}{\lambda}$, we can find the maximum wavelength $\lambda$ as $\lambda = \frac{hc}{E}$.Substituting the values $h = 6.62 	imes 10^{-34} 	ext{ J s}$, $c = 3 	imes 10^8 	ext{ m/s}$, and $E = 57 	imes 10^{-3} 	imes 1.6 	imes 10^{-19} 	ext{ J}$:$\lambda = \frac{6.62 	imes 10^{-34} 	imes 3 	imes 10^8}{57 	imes 10^{-3} 	imes 1.6 	imes 10^{-19}} 	ext{ m}$.$\lambda \approx 2.171 	imes 10^{-5} 	ext{ m}$.Converting to $\mathring{A}$s $(\mathring{A})$, where $1 	ext{ m} = 10^{10} \mathring{A}$:$\lambda = 2.171 	imes 10^{-5} 	imes 10^{10} \mathring{A} = 217100 \mathring{A}$.

In a $P$-type semiconductor, the acceptor level is $57 \text{ meV}$ above the valence band. What is the maximum wavelength of light (in $\mathring{A}$) required to create a hole?

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