The correct relationship between alpha and be | vedclass

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(B) We know that the current gain in common base configuration is $\alpha = \frac{\Delta i_C}{\Delta i_E}$.We know that the current gain in common emi

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$\beta = \frac{\alpha}{1 - \alpha}$

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(B) We know that the current gain in common base configuration is $\alpha = \frac{\Delta i_C}{\Delta i_E}$.We know that the current gain in common emitter configuration is $\beta = \frac{\Delta i_C}{\Delta i_B}$.Since the emitter current is the sum of collector and base currents,we have $\Delta i_E = \Delta i_C + \Delta i_B$,which implies $\Delta i_B = \Delta i_E - \Delta i_C$.Substituting this into the expression for $\beta$:$\beta = \frac{\Delta i_C}{\Delta i_E - \Delta i_C}$.Dividing the numerator and denominator by $\Delta i_E$:$\beta = \frac{\frac{\Delta i_C}{\Delta i_E}}{1 - \frac{\Delta i_C}{\Delta i_E}}$.Since $\alpha = \frac{\Delta i_C}{\Delta i_E}$,we get:$\beta = \frac{\alpha}{1 - \alpha}$.

The correct relationship between $\alpha$ and $\beta$ for a transistor is ........

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