Germanium $(Ge)$ is doped with Aluminum $(Al)$. If the concentration of acceptor atoms is $N_A \cong 10^{21} \text{ atoms/m}^3$ and the intrinsic carrier concentration is $n_i = 10^{19} \text{ m}^{-3}$,then the concentration of electrons is:

  • A
    $10^{17} \text{ m}^{-3}$
  • B
    $10^{15} \text{ m}^{-3}$
  • C
    $10^4 \text{ m}^{-3}$
  • D
    $10^2 \text{ m}^{-3}$

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In an intrinsic semiconductor,the density of conduction electrons is $7.07 \times 10^{15} \, m^{-3}$. When it is doped with indium,the density of holes becomes $5 \times 10^{22} \, m^{-3}$. Find the density of conduction electrons in the doped semiconductor.

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