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(B) In circuit $1$,the two diodes are connected in opposite directions (one forward biased,one reverse biased). The reverse biased diode acts as a hig

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In circuits $2$ and $3$

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(B) In circuit $1$,the two diodes are connected in opposite directions (one forward biased,one reverse biased). The reverse biased diode acts as a high resistance,so almost the entire battery voltage appears across it.In circuit $2$,both diodes are forward biased. They share the battery voltage equally,so each has a potential difference of $V/2$.In circuit $3$,both diodes are reverse biased. They share the battery voltage equally,so each has a potential difference of $V/2$.Since the potential difference across each diode in circuit $2$ and circuit $3$ is $V/2$,the potential difference is equal in circuits $2$ and $3$.

Two identical $P-N$ junctions are connected in series with a battery in three ways as shown in the figure. In which two circuits will the potential difference across the $P-N$ junctions be equal?

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