For $I_b = 20 \ \mu A$ and $\beta = 100$,the value of the emitter current is ........ $mA$.

For a transistor,$\alpha$ and $\beta$ are given as $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$. Then the correct relation between $\alpha$ and $\beta$ is:

In common emitter mode of a transistor, the current gain is $8$. The input impedance is $25 \, k\Omega$ and load resistance is $75 \, k\Omega$. The power gain is

What is the voltage gain in a common emitter amplifier,where input resistance is $3 \, \Omega$ and load resistance is $24 \, \Omega$,and the current gain $\beta = 0.6$?

In case of a bipolar transistor, $\beta = 45$. The potential drop across the collector resistance of $1 \ k\Omega$ is $5 \ V$. The base current is approximately: (in $\mu A$)

In a common emitter amplifier,the current gain is $62$. The collector resistance and input resistance are $5\,k\Omega$ and $500\,\Omega$ respectively. If the input voltage is $0.01\,V$,the output voltage is $..........\,V$.