$A$ common emitter circuit is used as an amplifier with a current gain of $50$. If the input resistance is $1 \ k\Omega$ and the input voltage is $5 \ V$, then the output current is ....... $mA$.

An $NPN$ transistor circuit is arranged as shown in the figure. It is:

For a common emitter transistor,the current gain is $50$,the input resistance is $1 \ k\Omega$,and the input voltage is $0.01 \ V$. What is the collector current?

The input characteristics of a transistor in $CE$ mode is the graph obtained by plotting

$A$ transistor is used in an amplifier circuit in common emitter mode. If the base current changes by $100 \,\mu A$, it brings a change of $10 \,mA$ in collector current. If the load resistance is $2 \,k \Omega$ and input resistance is $1 \,k \Omega$, the value of power gain is $x \times 10^{4}$. The value of $x$ is . . . . . . .

In a common emitter transistor amplifier, an input signal of $10 \ mV$ is applied. Due to this signal, the change in base current is $50 \ \mu A$ and the corresponding change in collector current is $5 \ mA$. If the load resistance in the collector-emitter circuit is $5 \ k\Omega$, the change in output voltage will be ..... $V$.