In an $NPN$ transistor circuit,the collector current is $10 \ mA$. If $95\%$ of the electrons emitted reach the collector,what is the base current in $mA$?

In the figure,given that $V_{BB}$ supply can vary from $0$ to $5.0 \,V$,$V_{CC} = 5\,V$,$\beta_{dc} = 200$,$R_B = 100\,k\Omega$,$R_C = 1\,k\Omega$ and $V_{BE} = 1.0\,V$. The minimum base current and the input voltage at which the transistor will go to saturation,will be respectively:

The output characteristics of a transistor are shown in the figure. When $V_{CE} = 10\, V$ and $I_{C} = 4.0\, mA$,then the value of $\beta_{ac}$ is:

Which one of the operations of $n-p-n$ transistor differs from that of $p-n-p$ transistor?

In $n-p-n$ transistor, in $CE$ configuration:

In a common emitter amplifier configuration, the current gain is $62$. The collector resistance and input resistance are $5 \text{ k}\Omega$ and $500 \text{ }\Omega$ respectively. If the input voltage is $0.01 \text{ V}$, the output voltage will be (in $V$)