A magnifying lens has a focal length of 10 , | vedclass

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(C) In the case of a magnifying lens (convex lens used as a simple magnifier),the image formed is virtual,erect,and magnified on the same side as the

Vedclass · Accepted Answer

$7.5$

Vedclass · Answer

(C) In the case of a magnifying lens (convex lens used as a simple magnifier),the image formed is virtual,erect,and magnified on the same side as the object.Given: Focal length $f = +10 \, cm$ (for a convex lens).Since the image is virtual,the image distance $v = -30 \, cm$.Using the lens formula: $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$Substituting the values: $\frac{1}{-30} - \frac{1}{u} = \frac{1}{10}$Rearranging the terms: $-\frac{1}{u} = \frac{1}{10} + \frac{1}{30}$$-\frac{1}{u} = \frac{3 + 1}{30} = \frac{4}{30}$$-\frac{1}{u} = \frac{2}{15}$$u = -7.5 \, cm$The negative sign indicates that the object is placed in front of the lens at a distance of $7.5 \, cm$.

$A$ magnifying lens has a focal length of $10 \, cm$. If an image is to be formed at a distance of $30 \, cm$ from the lens,the object should be placed at a distance of ..... $cm$.

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