A hollow double concave lens is made of very | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The focal length $f$ of a lens is given by the Lens Maker's formula:$\frac{1}{f} = \left( \frac{n_L}{n_m} - 1 \right) \left( \frac{1}{R_1} - \frac

Vedclass · Accepted Answer

$L_2$ and immersed in $L_1$

Vedclass · Answer

(D) The focal length $f$ of a lens is given by the Lens Maker's formula:$\frac{1}{f} = \left( \frac{n_L}{n_m} - 1 \right) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$where $n_L$ is the refractive index of the lens material and $n_m$ is the refractive index of the surrounding medium.For a double concave lens,the term $\left( \frac{1}{R_1} - \frac{1}{R_2} \right)$ is negative.For the lens to diverge light,it must act as a concave lens,meaning its focal length $f$ must be negative.Since $\left( \frac{1}{R_1} - \frac{1}{R_2} \right) This implies $\frac{n_L}{n_m} > 1$,or $n_L > n_m$.In option $(d)$,the lens is filled with liquid $L_2$ (refractive index $n_2$) and immersed in liquid $L_1$ (refractive index $n_1$). Since $n_2 > n_1$,the condition $n_L > n_m$ is satisfied,and the lens will diverge the light.

$A$ hollow double concave lens is made of very thin transparent material. It can be filled with air or either of two liquids $L_1$ and $L_2$ having refractive indices $n_1$ and $n_2$ respectively $(n_2 > n_1 > 1)$. The lens will diverge a parallel beam of light if it is filled with

Similar Questions

For a convex lens,if a real image is formed,the graph between $(u + v)$ and $u$ or $v$ is as follows:

$A$ convex lens has its radii of curvature equal. The focal length of the lens is $f$. If it is divided vertically into two identical plano-convex lenses by cutting it, then the focal length of the plano-convex lens is ($\mu =$ the refractive index of the material of the lens).

The refractive index of the material of a concave lens is $\mu$. It is immersed in a medium of refractive index $\mu_1$. $A$ parallel beam of light is incident on the lens. The path of the emergent rays when $\mu_1 > \mu$ is

The diameter of the Sun is $1.4 \times 10^9 \, m$ and its distance from the Earth is $10^{11} \, m$. What is the diameter of the image (in $cm$) formed by a convex lens of focal length $2 \, m$?

An object is located in a fixed position in front of a screen. $A$ sharp image is obtained on the screen for two positions of a thin lens separated by $10\, cm$. The size of the images in the two situations are in the ratio $3 : 2$. What is the distance between the screen and the object in $cm$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module