$A$ light ray is incident on a prism of prism angle $60^{\circ}$ such that it undergoes minimum deviation. If the refractive index of the prism is $\sqrt{2}$,then the angle of incidence is .......$^{\circ}$.

$A$ ray of light suffers a minimum deviation when incident on an equilateral prism of refractive index $ \sqrt{2} $. The angle of incidence is (in $^{\circ}$)

An equilateral prism $P$ produces a minimum deviation for a given light ray. Additional prisms $Q$ and $R$ of the same shape and material are placed as shown in the figure. The ray will experience:

Angle of minimum deviation is equal to the half of the angle of prism in an equilateral prism. The refractive index of the prism is . . . . . . .

$A$ plot between the angle of deviation and angle of incidence is shown in the figure. From the graph,one can say that the prism angle is ....... (in $^{\circ}$)

$A$ ray of monochromatic light is passing through an equilateral prism $(ABC)$ as shown in the figure. The refracted ray $(QR)$ is parallel to its base $(BC)$ and the angle of incidence $(i)$ is $50^\circ$. Then the angle of deviation $(\delta)$ is: (in $^\circ$)