Two bulbs have resistances in the ratio 1 : 2 | vedclass

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(C) Let the resistances of the two bulbs be $R_1 = R$ and $R_2 = 2R$.When components are connected in parallel,the voltage $V$ across each component r

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$2/1$

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(C) Let the resistances of the two bulbs be $R_1 = R$ and $R_2 = 2R$.When components are connected in parallel,the voltage $V$ across each component remains the same.The power dissipated in a resistor is given by the formula $P = \frac{V^2}{R}$.For the first bulb,$P_1 = \frac{V^2}{R}$.For the second bulb,$P_2 = \frac{V^2}{2R}$.Taking the ratio of the power dissipated:$\frac{P_1}{P_2} = \frac{V^2/R}{V^2/2R} = \frac{2R}{R} = \frac{2}{1}$.

Two bulbs have resistances in the ratio $1 : 2$. They are connected in parallel to a constant voltage source. What is the ratio of power dissipated in them?

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