There are four bulbs of power 100 ,W, 200 ,W, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The power $P$ consumed by a bulb is given by the formula $P = \frac{V^2}{R}$, where $V$ is the voltage and $R$ is the resistance of the filament.S

Vedclass · Accepted Answer

$100 \,W$ bulb

Vedclass · Answer

(A) The power $P$ consumed by a bulb is given by the formula $P = \frac{V^2}{R}$, where $V$ is the voltage and $R$ is the resistance of the filament.Since the voltage source is the same for all bulbs, $V$ is constant.Therefore, the relationship between power and resistance is $R = \frac{V^2}{P}$, which implies $R \propto \frac{1}{P}$.This means that the resistance is inversely proportional to the power rating of the bulb.To have the highest resistance, the bulb must have the lowest power rating.Comparing the given powers $(100 \,W, 200 \,W, 500 \,W, 1000 \,W)$, the $100 \,W$ bulb has the lowest power.Thus, the $100 \,W$ bulb filament has the highest resistance.

There are four bulbs of power $100 \,W, 200 \,W, 500 \,W$ and $1000 \,W$. Among these, which filament has the highest resistance? (Assuming the same voltage source)

Similar Questions

$5.0 \, A$ current is set up in an external circuit by a $6.0 \, V$ storage battery for $6.0 \, \text{minutes}$. The chemical energy of the battery is reduced by:

Assertion: Long distance power transmission is done at high voltage.
Reason: At high voltage supply,power losses are less.

The power rating of an electric motor which draws a current of $3.75\, A$ when operated at $200\, V$ is about:

How much heat (in $cal$) is produced when a $210 \, W$ bulb is kept on for $5 \, min$? (Given $J = 4.2 \, J/cal$)

$A$ time-varying current $i$ is passed through a resistance $R$ as shown in the figure. The total heat generated in the resistance is

Vedclass Test Series

Exam Paper Generator

Online Exam Module