P and Q are two identical wires of resistance | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The total resistance of the wire $PQ$ is $2000\, \Omega$. Since $M$ is the midpoint, the resistance of segment $PM$ is $1000\, \Omega$ and the res

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(D) The total resistance of the wire $PQ$ is $2000\, \Omega$. Since $M$ is the midpoint, the resistance of segment $PM$ is $1000\, \Omega$ and the resistance of segment $MQ$ is $1000\, \Omega$.The voltmeter of resistance $R_v = 1000\, \Omega$ is connected in parallel with the segment $PM$ $(R_{PM} = 1000\, \Omega)$.The equivalent resistance of the parallel combination of the voltmeter and segment $PM$ is:$R_p = \frac{R_v 	imes R_{PM}}{R_v + R_{PM}} = \frac{1000 	imes 1000}{1000 + 1000} = 500\, \Omega$.The total resistance of the circuit is $R_{eq} = R_p + R_{MQ} = 500\, \Omega + 1000\, \Omega = 1500\, \Omega$.The total current in the circuit is $I = \frac{V}{R_{eq}} = \frac{150\, V}{1500\, \Omega} = 0.1\, A$.The voltage across the parallel combination (which is the voltmeter reading) is $V_v = I 	imes R_p = 0.1\, A 	imes 500\, \Omega = 50\, V$.

Similar Questions

The charge flowing through a resistance $R$ varies with time $t$ as $Q = at - bt^2$,where $a$ and $b$ are positive constants. The total heat produced in $R$ is

When a resistance of $9 \,\Omega$ is connected across the terminals of a battery,its potential difference decreases from $40 \, V$ to $30 \, V$. The internal resistance of the battery is ............... $\Omega$.

An electric bulb rated for $500\, W$ at $100\, V$ is used in a circuit having a $200\, V$ supply. The resistance $R$ that must be put in series with the bulb,so that the bulb draws $500\, W$,is ................. $\Omega$.

Refer to the circuit shown. What will be the total power dissipation in the circuit if $P$ is the power dissipated in $R_1$ (in $P$)? It is given that $R_2 = 4 R_1$ and $R_3 = 12 R_1$.

In the given circuit diagram,the galvanometer reading is zero. If the internal resistance of the cell is neglected,then the value of $X$ is ......... $\Omega$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module