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(B) The electromotive force $(E)$ of the battery is $40 \, V$ (the potential difference when no current is drawn).When a resistance $R = 9 \,\Omega$ i

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$3$

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(B) The electromotive force $(E)$ of the battery is $40 \, V$ (the potential difference when no current is drawn).When a resistance $R = 9 \,\Omega$ is connected,the terminal potential difference $(V)$ becomes $30 \, V$.The formula for internal resistance $(r)$ is given by:$r = \left( \frac{E}{V} - 1 ight) R$Substituting the given values:$r = \left( \frac{40}{30} - 1 ight) 	imes 9$$r = \left( \frac{4}{3} - 1 ight) 	imes 9$$r = \left( \frac{1}{3} ight) 	imes 9$$r = 3 \,\Omega$.

When a resistance of $9 \,\Omega$ is connected across the terminals of a battery,its potential difference decreases from $40 \, V$ to $30 \, V$. The internal resistance of the battery is ............... $\Omega$.

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