Two bulbs are in parallel and they together c | vedclass

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(D) The bulbs are connected in parallel,so the voltage across each bulb is the same as the battery voltage,$V = 6\, V$.Since the two bulbs consume a t

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$1.5$

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(D) The bulbs are connected in parallel,so the voltage across each bulb is the same as the battery voltage,$V = 6\, V$.Since the two bulbs consume a total power of $P_{total} = 48\, W$,and they are identical (implied by the question asking for the resistance of 'each' bulb),each bulb consumes $P = \frac{48}{2} = 24\, W$.The power consumed by a resistor is given by the formula $P = \frac{V^2}{R}$.Rearranging for resistance,we get $R = \frac{V^2}{P}$.Substituting the values,$R = \frac{6^2}{24} = \frac{36}{24} = 1.5\, \Omega$.Therefore,the resistance of each bulb is $1.5\, \Omega$.

Two bulbs are in parallel and they together consume $48\, W$ from a battery of $6\, V$. The resistance of each bulb is ............ $\Omega$.

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