Two resistors whose values are in the ratio 2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When resistors are connected in parallel,the potential difference $(V)$ across each resistor is the same.The power dissipated $(P)$ in a resistor

Vedclass · Accepted Answer

$1:2$

Vedclass · Answer

(C) When resistors are connected in parallel,the potential difference $(V)$ across each resistor is the same.The power dissipated $(P)$ in a resistor is given by the formula $P = \frac{V^2}{R}$.Since $V$ is constant,the power dissipated is inversely proportional to the resistance: $P \propto \frac{1}{R}$.Given the ratio of resistances is $\frac{R_1}{R_2} = \frac{2}{1}$.Therefore,the ratio of power dissipated is $\frac{P_1}{P_2} = \frac{R_2}{R_1} = \frac{1}{2}$.

Two resistors whose values are in the ratio $2 : 1$ are connected in parallel with one cell. The ratio of power dissipated is:

Similar Questions

When a resistance of $2\,\Omega$ is connected across the terminals of a cell,the current is $0.5\,A$. When the resistance is increased to $5\,\Omega$,the current is $0.25\,A$. The $e.m.f.$ of the cell is ................. $V$.

In the given circuit,find $V_a - V_b$.

In the circuit given below,if the bulb is to glow with maximum intensity,the value of $R$ is (neglect internal resistance of the cell) (in $\Omega$)

The potential drop across the $3 \,\Omega$ resistor is ............... $V$.

$A$ potential divider is used to give outputs of $4\,V$ and $8\,V$ from a $12\,V$ source. Which combination of resistances,$(R_1 : R_2 : R_3)$ gives the correct voltages?

Vedclass Test Series

Exam Paper Generator

Online Exam Module