The resistance of a resistance wire is 5,Omeg | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The resistance at temperature $	heta$ is given by $R_{	heta} = R_0(1 + \alpha	heta)$,where $R_0$ is the resistance at $0\,^{\circ}	ext{C}$.At

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) The resistance at temperature $	heta$ is given by $R_{	heta} = R_0(1 + \alpha	heta)$,where $R_0$ is the resistance at $0\,^{\circ}	ext{C}$.At $50\,^{\circ}	ext{C}$,$5 = R_0(1 + 50\alpha)$ ... $(1)$At $100\,^{\circ}	ext{C}$,$6 = R_0(1 + 100\alpha)$ ... $(2)$Dividing equation $(1)$ by equation $(2)$:$\frac{5}{6} = \frac{1 + 50\alpha}{1 + 100\alpha}$$5(1 + 100\alpha) = 6(1 + 50\alpha)$$5 + 500\alpha = 6 + 300\alpha$$200\alpha = 1 \implies \alpha = \frac{1}{200}$Substituting $\alpha$ in equation $(1)$:$5 = R_0(1 + 50 	imes \frac{1}{200})$$5 = R_0(1 + \frac{1}{4})$$5 = R_0(\frac{5}{4})$$R_0 = 4\,\Omega$.

The resistance of a resistance wire is $5\,\Omega$ at $50\,^{\circ}\text{C}$ and $6\,\Omega$ at $100\,^{\circ}\text{C}$. The resistance at $0\,^{\circ}\text{C}$ will be ............. $\Omega$.

Similar Questions

The resistance of a bulb filament is $100\,\Omega$ at a temperature of $100\,^{\circ}C$. If its temperature coefficient of resistance is $0.005\,^{\circ}C^{-1}$,at what temperature will its resistance become $200\,\Omega$?

What is electrical resistance $(R)$? On which factors does the resistance value depend?

The new resistance of a wire of $R \, \Omega$,whose radius is reduced to half,is

Two wires of equal length and equal diameter and having resistivities $\rho_1$ and $\rho_2$ are connected in series. The equivalent resistivity of the combination is . . . . . . .

An aluminium (resistivity $\rho = 2.2 \times 10^{-8} \Omega \cdot m$) wire of diameter $1.4 \text{ mm}$ is used to make a $4 \Omega$ resistor. The length of the wire is: (in $\text{ m}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module