The value of frac{d}{dx} (cos 4x^2) is ...... | vedclass

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(D) To find the derivative of $\cos 4x^2$ with respect to $x$,we use the chain rule.Let $u = 4x^2$,then $\frac{d}{dx} (\cos u) = -\sin u \cdot \frac{d

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$-8x \sin 4x^2$

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(D) To find the derivative of $\cos 4x^2$ with respect to $x$,we use the chain rule.Let $u = 4x^2$,then $\frac{d}{dx} (\cos u) = -\sin u \cdot \frac{du}{dx}$.$\frac{d}{dx} (\cos 4x^2) = -\sin(4x^2) \cdot \frac{d}{dx}(4x^2)$.Since $\frac{d}{dx}(4x^2) = 4 \cdot 2x = 8x$,we get $\frac{d}{dx} (\cos 4x^2) = -\sin(4x^2) \cdot 8x = -8x \sin 4x^2$.

The value of $\frac{d}{dx} (\cos 4x^2)$ is .......

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