If the vector vec{P} = 3hat{i} + 4hat{j} + 12 | vedclass

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(C) The magnitude of a vector $\vec{P} = P_x\hat{i} + P_y\hat{j} + P_z\hat{k}$ is given by the formula $|\vec{P}| = \sqrt{P_x^2 + P_y^2 + P_z^2}$.Give

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$13$

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(C) The magnitude of a vector $\vec{P} = P_x\hat{i} + P_y\hat{j} + P_z\hat{k}$ is given by the formula $|\vec{P}| = \sqrt{P_x^2 + P_y^2 + P_z^2}$.Given $\vec{P} = 3\hat{i} + 4\hat{j} + 12\hat{k}$,we have $P_x = 3$,$P_y = 4$,and $P_z = 12$.Substituting these values into the formula:$|\vec{P}| = \sqrt{3^2 + 4^2 + 12^2}$$|\vec{P}| = \sqrt{9 + 16 + 144}$$|\vec{P}| = \sqrt{169}$$|\vec{P}| = 13$.

Column $-I$	Column $-II$
$(1)$ Angular momentum	$(a)$ Scalar
$(2)$ Potential energy	$(b)$ Vector
	$(c)$ Unit vector

If the vector $\vec{P} = 3\hat{i} + 4\hat{j} + 12\hat{k}$,then the magnitude of the vector $\vec{P}$ is ......

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