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(C) The magnitude of the resultant vector $\vec{C} = \vec{A} + \vec{B}$ is given by $C^2 = A^2 + B^2 + 2AB \cos 	heta$,where $	heta$ is the angle be

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$\vec{A}$ is perpendicular to $\vec{B}$.

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(C) The magnitude of the resultant vector $\vec{C} = \vec{A} + \vec{B}$ is given by $C^2 = A^2 + B^2 + 2AB \cos 	heta$,where $	heta$ is the angle between $\vec{A}$ and $\vec{B}$.Given that $C^2 = A^2 + B^2$,we substitute this into the equation:$A^2 + B^2 = A^2 + B^2 + 2AB \cos 	heta$.Subtracting $A^2 + B^2$ from both sides,we get:$0 = 2AB \cos 	heta$.Since the magnitudes $A$ and $B$ are non-zero,we must have $\cos 	heta = 0$.This implies $	heta = 90^\circ$.Therefore,$\vec{A}$ is perpendicular to $\vec{B}$.

Given two vectors $\vec{A}$ and $\vec{B}$,such that $\vec{A} + \vec{B} = \vec{C}$ and $A^2 + B^2 = C^2$. Which of the following statements is true?

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