The ratio of intensities of two interfering waves is $9:1$. The ratio of the maximum amplitude to the minimum amplitude of the resultant wave is ........

The intensity ratio of two coherent sources of light is $p$. They are interfering in some region and produce an interference pattern. Then the fringe visibility is

In a Young's double slit experiment,the intensity at a point where the path difference is $\frac{\lambda}{6}$ ($\lambda$ being the wavelength of light used) is $I$. If $I_0$ denotes the maximum intensity,then $\frac{I}{I_0} = $ . . . . . .

The amplitude of the light waves emerging from the two slits in Young's experiment is in the ratio of $2 : 3$. The ratio of the intensity of the minimum to that of the consecutive maximum will be:

Two coherent sources with intensity ratio $\beta : 1$ produce interference. Fringe visibility will be

In Young's double-slit experiment,if the ratio of the widths of the two slits is $4:9$,then the ratio of the maximum to minimum intensity will be: