The refractive index of glass for red light i | vedclass

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(A) For a thin prism,the angle of deviation is given by $D = (\mu - 1) A$,where $\mu$ is the refractive index and $A$ is the angle of the prism.Since

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$D_1 < D_2$

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(A) For a thin prism,the angle of deviation is given by $D = (\mu - 1) A$,where $\mu$ is the refractive index and $A$ is the angle of the prism.Since the refractive index for blue light $(\mu_{blue} = 1.525)$ is greater than the refractive index for red light $(\mu_{red} = 1.520)$,we have $\mu_{blue} > \mu_{red}$.Substituting this into the deviation formula,we get $D_{blue} > D_{red}$.Given $D_1$ is the deviation for red light and $D_2$ is the deviation for blue light,we conclude that $D_2 > D_1$ or $D_1 < D_2$.

The refractive index of glass for red light is $1.520$ and for blue light is $1.525$. Suppose the deviations of red and blue light in a prism of this glass are $D_1$ and $D_2$ respectively. Then .....

Similar Questions

The angle of deviation $\delta$ produced by a prism of refractive index $\mu$ and small refracting angle $A$ is given by:

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