(B) The shift in the fringe pattern is given by the formula: $\Delta x = \frac{(\mu - 1) t D}{d}$Given:Refractive index $\mu = 1.5$Thickness $t = 2.5

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(B) The shift in the fringe pattern is given by the formula: $\Delta x = \frac{(\mu - 1) t D}{d}$Given:Refractive index $\mu = 1.5$Thickness $t = 2.5 \times 10^{-5} \, m$Distance between slits $d = 0.5 \, mm = 0.5 \times 10^{-3} \, m$Distance to screen $D = 100 \, cm = 1 \, m$Substituting the values:$\Delta x = \frac{(1.5 - 1) \times (2.5 \times 10^{-5}) \times 1}{0.5 \times 10^{-3}}$$\Delta x = \frac{0.5 \times 2.5 \times 10^{-5}}{0.5 \times 10^{-3}}$$\Delta x = 2.5 \times 10^{-2} \, m$$\Delta x = 2.5 \, cm$

Class 12 Physics Wave Optics Variations in YDSE (Young's Double Slit Experiment)

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In a Young's double-slit experiment,a transparent plate of thickness $2.5 \times 10^{-5} \, m$ and refractive index $1.5$ is placed in the path of one of the beams. What will be the shift in the fringe pattern (in $, cm$)? The distance between the two slits $S_1$ and $S_2$ is $0.5 \, mm$ and the distance between the slits and the screen is $100 \, cm$.

A
$5$
B
$2.5$
C
$0.25$
D
$0.1$

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Variations in YDSE (Young's Double Slit Experiment)

In the ideal double-slit experiment,when a glass plate (refractive index $\mu = 1.5$) of thickness $t$ is introduced in the path of one of the interfering beams (wavelength $\lambda$),the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass plate is:

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In Young's double slit arrangement,water is filled in the space between the screen and the slits. Then:

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The slits in a double-slit interference experiment are illuminated by orange light $(\lambda = 600 \ nm)$. $A$ thin transparent plastic sheet of thickness $t$ is placed in front of one of the slits. The number of fringes $(N)$ shifting on the screen is plotted versus the refractive index $\mu$ of the plastic in the graph shown. The value of $t$ is

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In the $YDSE$ shown,the two slits are covered with thin sheets having thickness $t$ and $2t$,and refractive index $2\mu$ and $\mu$ respectively. Find the position $(y)$ of the central maxima.

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The figure shows a double-slit experiment. Each slit has a width $W$. $A$ thin glass slab of thickness $\delta$ and refractive index $\mu$ is placed in front of one of the slits. The intensity at the central point $C$ is measured as a function of the thickness $\delta$. At what thickness $\delta$ will the intensity at $C$ be minimum?

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In Young's double slit arrangement,water is filled in the space between the screen and the slits. Then:

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