What is the sum of the infinite series sqrt{3 | vedclass

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Question

(C) The given series is $\sqrt{3} + \frac{1}{\sqrt{3}} + \frac{1}{3\sqrt{3}} + \dots$ This is an infinite geometric series with the first term $a = \s

Vedclass · Accepted Answer

$\frac{3\sqrt{3}}{2}$

Vedclass · Answer

(C) The given series is $\sqrt{3} + \frac{1}{\sqrt{3}} + \frac{1}{3\sqrt{3}} + \dots$ This is an infinite geometric series with the first term $a = \sqrt{3}$. The common ratio $r$ is given by $r = \frac{T_2}{T_1} = \frac{1/\sqrt{3}}{\sqrt{3}} = \frac{1}{3}$. Since $|r| Substituting the values,$S = \frac{\sqrt{3}}{1 - 1/3} = \frac{\sqrt{3}}{2/3} = \frac{3\sqrt{3}}{2}$. Thus,the correct option is $C$.

What is the sum of the infinite series $\sqrt{3} + \frac{1}{\sqrt{3}} + \frac{1}{3\sqrt{3}} + \dots$?

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