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(B) Let the infinite geometric series be $a, ar, ar^2, ar^3, \dots$ where $a = 1$.According to the problem,each term is equal to the sum of all subseq

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$1/8$

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(B) Let the infinite geometric series be $a, ar, ar^2, ar^3, \dots$ where $a = 1$.According to the problem,each term is equal to the sum of all subsequent terms.For the first term: $a = ar + ar^2 + ar^3 + \dots$Since $a = 1$,we have $1 = ar + ar^2 + ar^3 + \dots$This is an infinite geometric series with first term $ar$ and common ratio $r$.The sum of an infinite geometric series is given by $S = \frac{	ext{first term}}{1 - r}$.So,$1 = \frac{ar}{1 - r}$.Substituting $a = 1$: $1 = \frac{r}{1 - r}$.$1 - r = r \implies 2r = 1 \implies r = 1/2$.The fourth term is $T_4 = ar^3$.$T_4 = 1 	imes (1/2)^3 = 1/8$.

If the first term of an infinite geometric series is $1$ and each term is equal to the sum of all the terms that follow it,then what is its fourth term?

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