The four arithmetic means between 3 and 23 ar | vedclass

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(B) Let the four arithmetic means be $A_1, A_2, A_3,$ and $A_4$. Then,$3, A_1, A_2, A_3, A_4, 23$ are in an arithmetic progression. Here,the first ter

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$7, 11, 15, 19$

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(B) Let the four arithmetic means be $A_1, A_2, A_3,$ and $A_4$. Then,$3, A_1, A_2, A_3, A_4, 23$ are in an arithmetic progression. Here,the first term $a = 3$ and the $6^{th}$ term $t_6 = 23$. Using the formula $t_n = a + (n-1)d$: $23 = 3 + (6-1)d$ $23 = 3 + 5d$ $5d = 20$ $d = 4$ Now,calculating the means: $A_1 = a + d = 3 + 4 = 7$ $A_2 = a + 2d = 3 + 8 = 11$ $A_3 = a + 3d = 3 + 12 = 15$ $A_4 = a + 4d = 3 + 16 = 19$ Thus,the four arithmetic means are $7, 11, 15, 19$.

The four arithmetic means between $3$ and $23$ are.....

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