sim (p Leftrightarrow q) = dots | vedclass

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Question

(C) We know that $p \Leftrightarrow q$ is equivalent to $(p$ $\Rightarrow q) \wedge (q$ $\Rightarrow p)$.Therefore,$\sim (p \Leftrightarrow q) = \sim

Vedclass · Accepted Answer

$(\sim p \wedge q) \vee (p \wedge \sim q)$

Vedclass · Answer

(C) We know that $p \Leftrightarrow q$ is equivalent to $(p$ $\Rightarrow q) \wedge (q$ $\Rightarrow p)$.Therefore,$\sim (p \Leftrightarrow q) = \sim ((p$ $\Rightarrow q) \wedge (q$ $\Rightarrow p))$.Using De Morgan's Law,$\sim (A \wedge B) = \sim A \vee \sim B$,we get:$\sim (p$ $\Rightarrow q) \vee \sim (q$ $\Rightarrow p)$.Since $\sim (p \Rightarrow q) \equiv p \wedge \sim q$,the expression becomes:$(p \wedge \sim q) \vee (q \wedge \sim p)$.

$\sim (p \Leftrightarrow q) = \dots$

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