If $x$ is a real number,for what values of $x$ does $3x^2 + 14x + 11 > 0$ hold?

  • A
    $x < -\frac{11}{3}$
  • B
    $x < -\frac{11}{3} \text{ or } x > -1$
  • C
    $x > -1$
  • D
    $-\frac{11}{3} < x < -1$

Explore More

Similar Questions

The solution set of the inequation $\sqrt{x^2+6x+5} > (8-x)$ is

If $x^2-5x-14 > 0$ implies $x$ lies outside $[\alpha, \beta]$,then find the value of $\frac{\alpha}{\beta}$.

The sum of the fourth powers of the roots of the equation $x^3+x+1=0$ is

Let $S$ be the set of positive integral values of $a$ for which $\frac{ax^2+2(a+1)x+9a+4}{x^2-8x+32} < 0, \forall x \in R$. Then,the number of elements in $S$ is:

The set of all values of $x$ for which the inequalities $x^2-7x+10 \geq 0$ and $2x+3-x^2 > 0$ hold simultaneously is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo