If r and s are positive,what is the nature of | vedclass

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(C) The discriminant $D$ of the equation $ax^2 - rx - s = 0$ is given by $D = (-r)^2 - 4(a)(-s) = r^2 + 4as$.Since $r, s > 0$ and assuming $a > 0$,we

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Real and of opposite signs

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(C) The discriminant $D$ of the equation $ax^2 - rx - s = 0$ is given by $D = (-r)^2 - 4(a)(-s) = r^2 + 4as$.Since $r, s > 0$ and assuming $a > 0$,we have $D = r^2 + 4as > 0$,which implies the roots are real.Furthermore,the product of the roots is given by $\frac{c}{a} = \frac{-s}{a}$.Since $s > 0$ and $a > 0$,the product of the roots is negative,which implies that the roots must have opposite signs.

If $r$ and $s$ are positive,what is the nature of the roots of the quadratic equation $ax^2 - rx - s = 0$?

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