When three identical dice are thrown,what is | vedclass

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(B) When three dice are thrown,the total number of possible outcomes is $6 	imes 6 	imes 6 = 216$. The favorable outcomes where all three dice show

Vedclass · Accepted Answer

$1/36$

Vedclass · Answer

(B) When three dice are thrown,the total number of possible outcomes is $6 	imes 6 	imes 6 = 216$. The favorable outcomes where all three dice show the same number are: $(1, 1, 1), (2, 2, 2), (3, 3, 3), (4, 4, 4), (5, 5, 5), (6, 6, 6)$. There are $6$ such favorable outcomes. Therefore,the required probability is $P = \frac{6}{216} = \frac{1}{36}$.

When three identical dice are thrown,what is the probability of getting the same number on each of them?

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